Optimal. Leaf size=402 \[ -\frac{x \left (a+b x^n\right )^p \left (\frac{b x^n}{a}+1\right )^{-p} \left (-3 a^2 b c d^2 (n+1) (n (p+3)+1)+a^3 d^3 \left (2 n^2+3 n+1\right )+3 a b^2 c^2 d \left (n^2 \left (p^2+5 p+6\right )+n (2 p+5)+1\right )-b^3 c^3 \left (n^3 \left (p^3+6 p^2+11 p+6\right )+n^2 \left (3 p^2+12 p+11\right )+3 n (p+2)+1\right )\right ) \, _2F_1\left (\frac{1}{n},-p;1+\frac{1}{n};-\frac{b x^n}{a}\right )}{b^3 (n p+n+1) (n (p+2)+1) (n (p+3)+1)}+\frac{d x \left (a+b x^n\right )^{p+1} \left (a^2 d^2 \left (2 n^2+3 n+1\right )-a b c d \left (n^2 (p+7)+n (2 p+9)+2\right )+b^2 c^2 \left (n^2 \left (p^2+6 p+11\right )+2 n (p+3)+1\right )\right )}{b^3 (n p+n+1) (n (p+2)+1) (n (p+3)+1)}-\frac{d x \left (c+d x^n\right ) \left (a+b x^n\right )^{p+1} (a d (2 n+1)-b c (n (p+5)+1))}{b^2 (n (p+2)+1) (n (p+3)+1)}+\frac{d x \left (c+d x^n\right )^2 \left (a+b x^n\right )^{p+1}}{b (n p+3 n+1)} \]
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Rubi [A] time = 0.578185, antiderivative size = 401, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.263, Rules used = {416, 528, 388, 246, 245} \[ -\frac{x \left (a+b x^n\right )^p \left (\frac{b x^n}{a}+1\right )^{-p} \left (-3 a^2 b c d^2 (n+1) (n (p+3)+1)+a^3 d^3 \left (2 n^2+3 n+1\right )+3 a b^2 c^2 d \left (n^2 \left (p^2+5 p+6\right )+n (2 p+5)+1\right )-b^3 c^3 \left (n^3 \left (p^3+6 p^2+11 p+6\right )+n^2 \left (3 p^2+12 p+11\right )+3 n (p+2)+1\right )\right ) \, _2F_1\left (\frac{1}{n},-p;1+\frac{1}{n};-\frac{b x^n}{a}\right )}{b^3 (n p+n+1) (n (p+2)+1) (n (p+3)+1)}+\frac{d x \left (a+b x^n\right )^{p+1} \left (a^2 d^2 \left (2 n^2+3 n+1\right )-a b c d \left (n^2 (p+7)+n (2 p+9)+2\right )+b^2 c^2 \left (n^2 \left (p^2+6 p+11\right )+2 n (p+3)+1\right )\right )}{b^3 (n p+n+1) (n (p+2)+1) (n (p+3)+1)}-\frac{d x \left (c+d x^n\right ) \left (a+b x^n\right )^{p+1} (a d (2 n+1)-b (c n (p+5)+c))}{b^2 (n (p+2)+1) (n (p+3)+1)}+\frac{d x \left (c+d x^n\right )^2 \left (a+b x^n\right )^{p+1}}{b (n (p+3)+1)} \]
Antiderivative was successfully verified.
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Rule 416
Rule 528
Rule 388
Rule 246
Rule 245
Rubi steps
\begin{align*} \int \left (a+b x^n\right )^p \left (c+d x^n\right )^3 \, dx &=\frac{d x \left (a+b x^n\right )^{1+p} \left (c+d x^n\right )^2}{b (1+n (3+p))}+\frac{\int \left (a+b x^n\right )^p \left (c+d x^n\right ) \left (-c (a d-b (c+c n (3+p)))-d (a d (1+2 n)-b (c+c n (5+p))) x^n\right ) \, dx}{b (1+n (3+p))}\\ &=-\frac{d (a d (1+2 n)-b (c+c n (5+p))) x \left (a+b x^n\right )^{1+p} \left (c+d x^n\right )}{b^2 (1+n (2+p)) (1+n (3+p))}+\frac{d x \left (a+b x^n\right )^{1+p} \left (c+d x^n\right )^2}{b (1+n (3+p))}+\frac{\int \left (a+b x^n\right )^p \left (c \left (a^2 d^2 (1+2 n)-a b c d (2+n (7+2 p))+b^2 c^2 \left (1+n (5+2 p)+n^2 \left (6+5 p+p^2\right )\right )\right )+d \left (a^2 d^2 \left (1+3 n+2 n^2\right )-a b c d \left (2+n^2 (7+p)+n (9+2 p)\right )+b^2 c^2 \left (1+2 n (3+p)+n^2 \left (11+6 p+p^2\right )\right )\right ) x^n\right ) \, dx}{b^2 (1+n (2+p)) (1+n (3+p))}\\ &=\frac{d \left (a^2 d^2 \left (1+3 n+2 n^2\right )-a b c d \left (2+n^2 (7+p)+n (9+2 p)\right )+b^2 c^2 \left (1+2 n (3+p)+n^2 \left (11+6 p+p^2\right )\right )\right ) x \left (a+b x^n\right )^{1+p}}{b^3 (1+n+n p) (1+n (2+p)) (1+n (3+p))}-\frac{d (a d (1+2 n)-b (c+c n (5+p))) x \left (a+b x^n\right )^{1+p} \left (c+d x^n\right )}{b^2 (1+n (2+p)) (1+n (3+p))}+\frac{d x \left (a+b x^n\right )^{1+p} \left (c+d x^n\right )^2}{b (1+n (3+p))}-\frac{\left (a^3 d^3 \left (1+3 n+2 n^2\right )-3 a^2 b c d^2 (1+n) (1+n (3+p))+3 a b^2 c^2 d \left (1+n (5+2 p)+n^2 \left (6+5 p+p^2\right )\right )-b^3 c^3 \left (1+3 n (2+p)+n^2 \left (11+12 p+3 p^2\right )+n^3 \left (6+11 p+6 p^2+p^3\right )\right )\right ) \int \left (a+b x^n\right )^p \, dx}{b^3 (1+n+n p) (1+n (2+p)) (1+n (3+p))}\\ &=\frac{d \left (a^2 d^2 \left (1+3 n+2 n^2\right )-a b c d \left (2+n^2 (7+p)+n (9+2 p)\right )+b^2 c^2 \left (1+2 n (3+p)+n^2 \left (11+6 p+p^2\right )\right )\right ) x \left (a+b x^n\right )^{1+p}}{b^3 (1+n+n p) (1+n (2+p)) (1+n (3+p))}-\frac{d (a d (1+2 n)-b (c+c n (5+p))) x \left (a+b x^n\right )^{1+p} \left (c+d x^n\right )}{b^2 (1+n (2+p)) (1+n (3+p))}+\frac{d x \left (a+b x^n\right )^{1+p} \left (c+d x^n\right )^2}{b (1+n (3+p))}-\frac{\left (\left (a^3 d^3 \left (1+3 n+2 n^2\right )-3 a^2 b c d^2 (1+n) (1+n (3+p))+3 a b^2 c^2 d \left (1+n (5+2 p)+n^2 \left (6+5 p+p^2\right )\right )-b^3 c^3 \left (1+3 n (2+p)+n^2 \left (11+12 p+3 p^2\right )+n^3 \left (6+11 p+6 p^2+p^3\right )\right )\right ) \left (a+b x^n\right )^p \left (1+\frac{b x^n}{a}\right )^{-p}\right ) \int \left (1+\frac{b x^n}{a}\right )^p \, dx}{b^3 (1+n+n p) (1+n (2+p)) (1+n (3+p))}\\ &=\frac{d \left (a^2 d^2 \left (1+3 n+2 n^2\right )-a b c d \left (2+n^2 (7+p)+n (9+2 p)\right )+b^2 c^2 \left (1+2 n (3+p)+n^2 \left (11+6 p+p^2\right )\right )\right ) x \left (a+b x^n\right )^{1+p}}{b^3 (1+n+n p) (1+n (2+p)) (1+n (3+p))}-\frac{d (a d (1+2 n)-b (c+c n (5+p))) x \left (a+b x^n\right )^{1+p} \left (c+d x^n\right )}{b^2 (1+n (2+p)) (1+n (3+p))}+\frac{d x \left (a+b x^n\right )^{1+p} \left (c+d x^n\right )^2}{b (1+n (3+p))}-\frac{\left (a^3 d^3 \left (1+3 n+2 n^2\right )-3 a^2 b c d^2 (1+n) (1+n (3+p))+3 a b^2 c^2 d \left (1+n (5+2 p)+n^2 \left (6+5 p+p^2\right )\right )-b^3 c^3 \left (1+3 n (2+p)+n^2 \left (11+12 p+3 p^2\right )+n^3 \left (6+11 p+6 p^2+p^3\right )\right )\right ) x \left (a+b x^n\right )^p \left (1+\frac{b x^n}{a}\right )^{-p} \, _2F_1\left (\frac{1}{n},-p;1+\frac{1}{n};-\frac{b x^n}{a}\right )}{b^3 (1+n+n p) (1+n (2+p)) (1+n (3+p))}\\ \end{align*}
Mathematica [A] time = 5.25378, size = 168, normalized size = 0.42 \[ x \left (a+b x^n\right )^p \left (\frac{b x^n}{a}+1\right )^{-p} \left (\frac{3 c^2 d x^n \, _2F_1\left (1+\frac{1}{n},-p;2+\frac{1}{n};-\frac{b x^n}{a}\right )}{n+1}+c^3 \, _2F_1\left (\frac{1}{n},-p;1+\frac{1}{n};-\frac{b x^n}{a}\right )+\frac{3 c d^2 x^{2 n} \, _2F_1\left (2+\frac{1}{n},-p;3+\frac{1}{n};-\frac{b x^n}{a}\right )}{2 n+1}+\frac{d^3 x^{3 n} \, _2F_1\left (3+\frac{1}{n},-p;4+\frac{1}{n};-\frac{b x^n}{a}\right )}{3 n+1}\right ) \]
Antiderivative was successfully verified.
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Maple [F] time = 0.623, size = 0, normalized size = 0. \begin{align*} \int \left ( a+b{x}^{n} \right ) ^{p} \left ( c+d{x}^{n} \right ) ^{3}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (d x^{n} + c\right )}^{3}{\left (b x^{n} + a\right )}^{p}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (d^{3} x^{3 \, n} + 3 \, c d^{2} x^{2 \, n} + 3 \, c^{2} d x^{n} + c^{3}\right )}{\left (b x^{n} + a\right )}^{p}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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